Optimal. Leaf size=447 \[ d^2 x \left (\frac{2 c x^n}{b-\sqrt{b^2-4 a c}}+1\right )^{-p} \left (\frac{2 c x^n}{\sqrt{b^2-4 a c}+b}+1\right )^{-p} \left (a+b x^n+c x^{2 n}\right )^p F_1\left (\frac{1}{n};-p,-p;1+\frac{1}{n};-\frac{2 c x^n}{b-\sqrt{b^2-4 a c}},-\frac{2 c x^n}{b+\sqrt{b^2-4 a c}}\right )+\frac{2 d e x^{n+1} \left (\frac{2 c x^n}{b-\sqrt{b^2-4 a c}}+1\right )^{-p} \left (\frac{2 c x^n}{\sqrt{b^2-4 a c}+b}+1\right )^{-p} \left (a+b x^n+c x^{2 n}\right )^p F_1\left (1+\frac{1}{n};-p,-p;2+\frac{1}{n};-\frac{2 c x^n}{b-\sqrt{b^2-4 a c}},-\frac{2 c x^n}{b+\sqrt{b^2-4 a c}}\right )}{n+1}+\frac{e^2 x^{2 n+1} \left (\frac{2 c x^n}{b-\sqrt{b^2-4 a c}}+1\right )^{-p} \left (\frac{2 c x^n}{\sqrt{b^2-4 a c}+b}+1\right )^{-p} \left (a+b x^n+c x^{2 n}\right )^p F_1\left (2+\frac{1}{n};-p,-p;3+\frac{1}{n};-\frac{2 c x^n}{b-\sqrt{b^2-4 a c}},-\frac{2 c x^n}{b+\sqrt{b^2-4 a c}}\right )}{2 n+1} \]
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Rubi [A] time = 0.99276, antiderivative size = 447, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 5, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.192 \[ d^2 x \left (\frac{2 c x^n}{b-\sqrt{b^2-4 a c}}+1\right )^{-p} \left (\frac{2 c x^n}{\sqrt{b^2-4 a c}+b}+1\right )^{-p} \left (a+b x^n+c x^{2 n}\right )^p F_1\left (\frac{1}{n};-p,-p;1+\frac{1}{n};-\frac{2 c x^n}{b-\sqrt{b^2-4 a c}},-\frac{2 c x^n}{b+\sqrt{b^2-4 a c}}\right )+\frac{2 d e x^{n+1} \left (\frac{2 c x^n}{b-\sqrt{b^2-4 a c}}+1\right )^{-p} \left (\frac{2 c x^n}{\sqrt{b^2-4 a c}+b}+1\right )^{-p} \left (a+b x^n+c x^{2 n}\right )^p F_1\left (1+\frac{1}{n};-p,-p;2+\frac{1}{n};-\frac{2 c x^n}{b-\sqrt{b^2-4 a c}},-\frac{2 c x^n}{b+\sqrt{b^2-4 a c}}\right )}{n+1}+\frac{e^2 x^{2 n+1} \left (\frac{2 c x^n}{b-\sqrt{b^2-4 a c}}+1\right )^{-p} \left (\frac{2 c x^n}{\sqrt{b^2-4 a c}+b}+1\right )^{-p} \left (a+b x^n+c x^{2 n}\right )^p F_1\left (2+\frac{1}{n};-p,-p;3+\frac{1}{n};-\frac{2 c x^n}{b-\sqrt{b^2-4 a c}},-\frac{2 c x^n}{b+\sqrt{b^2-4 a c}}\right )}{2 n+1} \]
Antiderivative was successfully verified.
[In] Int[(d + e*x^n)^2*(a + b*x^n + c*x^(2*n))^p,x]
[Out]
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Rubi in Sympy [A] time = 123.616, size = 382, normalized size = 0.85 \[ d^{2} x \left (\frac{2 c x^{n}}{b - \sqrt{- 4 a c + b^{2}}} + 1\right )^{- p} \left (\frac{2 c x^{n}}{b + \sqrt{- 4 a c + b^{2}}} + 1\right )^{- p} \left (a + b x^{n} + c x^{2 n}\right )^{p} \operatorname{appellf_{1}}{\left (\frac{1}{n},- p,- p,1 + \frac{1}{n},- \frac{2 c x^{n}}{b - \sqrt{- 4 a c + b^{2}}},- \frac{2 c x^{n}}{b + \sqrt{- 4 a c + b^{2}}} \right )} + \frac{2 d e x^{n + 1} \left (\frac{2 c x^{n}}{b - \sqrt{- 4 a c + b^{2}}} + 1\right )^{- p} \left (\frac{2 c x^{n}}{b + \sqrt{- 4 a c + b^{2}}} + 1\right )^{- p} \left (a + b x^{n} + c x^{2 n}\right )^{p} \operatorname{appellf_{1}}{\left (\frac{n + 1}{n},- p,- p,2 + \frac{1}{n},- \frac{2 c x^{n}}{b - \sqrt{- 4 a c + b^{2}}},- \frac{2 c x^{n}}{b + \sqrt{- 4 a c + b^{2}}} \right )}}{n + 1} + \frac{e^{2} x^{2 n + 1} \left (\frac{2 c x^{n}}{b - \sqrt{- 4 a c + b^{2}}} + 1\right )^{- p} \left (\frac{2 c x^{n}}{b + \sqrt{- 4 a c + b^{2}}} + 1\right )^{- p} \left (a + b x^{n} + c x^{2 n}\right )^{p} \operatorname{appellf_{1}}{\left (2 + \frac{1}{n},- p,- p,3 + \frac{1}{n},- \frac{2 c x^{n}}{b - \sqrt{- 4 a c + b^{2}}},- \frac{2 c x^{n}}{b + \sqrt{- 4 a c + b^{2}}} \right )}}{2 n + 1} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((d+e*x**n)**2*(a+b*x**n+c*x**(2*n))**p,x)
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Mathematica [B] time = 6.26088, size = 1522, normalized size = 3.4 \[ \frac{2^{-p} c \left (b+\sqrt{b^2-4 a c}\right ) d e (2 n+1) \left (x^n+\frac{b-\sqrt{b^2-4 a c}}{2 c}\right )^{-p} \left (\frac{2 c x^n+b-\sqrt{b^2-4 a c}}{c}\right )^{p+1} \left (\left (\sqrt{b^2-4 a c}-b\right ) x^n-2 a\right )^2 \left (\left (c x^n+b\right ) x^n+a\right )^{p-1} F_1\left (1+\frac{1}{n};-p,-p;2+\frac{1}{n};-\frac{2 c x^n}{b+\sqrt{b^2-4 a c}},\frac{2 c x^n}{\sqrt{b^2-4 a c}-b}\right ) x^{n+1}}{\left (\sqrt{b^2-4 a c}-b\right ) (n+1) \left (2 c x^n+b+\sqrt{b^2-4 a c}\right ) \left (n p x^n \left (\left (\sqrt{b^2-4 a c}-b\right ) F_1\left (2+\frac{1}{n};1-p,-p;3+\frac{1}{n};-\frac{2 c x^n}{b+\sqrt{b^2-4 a c}},\frac{2 c x^n}{\sqrt{b^2-4 a c}-b}\right )-\left (b+\sqrt{b^2-4 a c}\right ) F_1\left (2+\frac{1}{n};-p,1-p;3+\frac{1}{n};-\frac{2 c x^n}{b+\sqrt{b^2-4 a c}},\frac{2 c x^n}{\sqrt{b^2-4 a c}-b}\right )\right )-2 (2 n a+a) F_1\left (1+\frac{1}{n};-p,-p;2+\frac{1}{n};-\frac{2 c x^n}{b+\sqrt{b^2-4 a c}},\frac{2 c x^n}{\sqrt{b^2-4 a c}-b}\right )\right )}+\frac{2^{-p-1} c \left (b+\sqrt{b^2-4 a c}\right ) e^2 (3 n+1) \left (x^n+\frac{b-\sqrt{b^2-4 a c}}{2 c}\right )^{-p} \left (\frac{2 c x^n+b-\sqrt{b^2-4 a c}}{c}\right )^{p+1} \left (\left (\sqrt{b^2-4 a c}-b\right ) x^n-2 a\right )^2 \left (\left (c x^n+b\right ) x^n+a\right )^{p-1} F_1\left (2+\frac{1}{n};-p,-p;3+\frac{1}{n};-\frac{2 c x^n}{b+\sqrt{b^2-4 a c}},\frac{2 c x^n}{\sqrt{b^2-4 a c}-b}\right ) x^{2 n+1}}{\left (\sqrt{b^2-4 a c}-b\right ) (2 n+1) \left (2 c x^n+b+\sqrt{b^2-4 a c}\right ) \left (n p x^n \left (\left (\sqrt{b^2-4 a c}-b\right ) F_1\left (3+\frac{1}{n};1-p,-p;4+\frac{1}{n};-\frac{2 c x^n}{b+\sqrt{b^2-4 a c}},\frac{2 c x^n}{\sqrt{b^2-4 a c}-b}\right )-\left (b+\sqrt{b^2-4 a c}\right ) F_1\left (3+\frac{1}{n};-p,1-p;4+\frac{1}{n};-\frac{2 c x^n}{b+\sqrt{b^2-4 a c}},\frac{2 c x^n}{\sqrt{b^2-4 a c}-b}\right )\right )-2 (3 n a+a) F_1\left (2+\frac{1}{n};-p,-p;3+\frac{1}{n};-\frac{2 c x^n}{b+\sqrt{b^2-4 a c}},\frac{2 c x^n}{\sqrt{b^2-4 a c}-b}\right )\right )}-\frac{2^{-2 p-1} \left (b+\sqrt{b^2-4 a c}\right ) d^2 (n+1) \left (x^n+\frac{b-\sqrt{b^2-4 a c}}{2 c}\right )^{-p} \left (x^n+\frac{b+\sqrt{b^2-4 a c}}{2 c}\right )^{-p} \left (-2 c x^n-b+\sqrt{b^2-4 a c}\right ) \left (\frac{2 c x^n+b-\sqrt{b^2-4 a c}}{c}\right )^p \left (\frac{2 c x^n+b+\sqrt{b^2-4 a c}}{c}\right )^{p-1} \left (\left (\sqrt{b^2-4 a c}-b\right ) x^n-2 a\right )^2 \left (\left (c x^n+b\right ) x^n+a\right )^{p-1} F_1\left (\frac{1}{n};-p,-p;1+\frac{1}{n};-\frac{2 c x^n}{b+\sqrt{b^2-4 a c}},\frac{2 c x^n}{\sqrt{b^2-4 a c}-b}\right ) x}{c \left (\sqrt{b^2-4 a c}-b\right ) \left (\left (\sqrt{b^2-4 a c}-b\right ) n p F_1\left (1+\frac{1}{n};1-p,-p;2+\frac{1}{n};-\frac{2 c x^n}{b+\sqrt{b^2-4 a c}},\frac{2 c x^n}{\sqrt{b^2-4 a c}-b}\right ) x^n-\left (b+\sqrt{b^2-4 a c}\right ) n p F_1\left (1+\frac{1}{n};-p,1-p;2+\frac{1}{n};-\frac{2 c x^n}{b+\sqrt{b^2-4 a c}},\frac{2 c x^n}{\sqrt{b^2-4 a c}-b}\right ) x^n-2 a (n+1) F_1\left (\frac{1}{n};-p,-p;1+\frac{1}{n};-\frac{2 c x^n}{b+\sqrt{b^2-4 a c}},\frac{2 c x^n}{\sqrt{b^2-4 a c}-b}\right )\right )} \]
Warning: Unable to verify antiderivative.
[In] Integrate[(d + e*x^n)^2*(a + b*x^n + c*x^(2*n))^p,x]
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Maple [F] time = 0.134, size = 0, normalized size = 0. \[ \int \left ( d+e{x}^{n} \right ) ^{2} \left ( a+b{x}^{n}+c{x}^{2\,n} \right ) ^{p}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((d+e*x^n)^2*(a+b*x^n+c*x^(2*n))^p,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int{\left (e x^{n} + d\right )}^{2}{\left (c x^{2 \, n} + b x^{n} + a\right )}^{p}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((e*x^n + d)^2*(c*x^(2*n) + b*x^n + a)^p,x, algorithm="maxima")
[Out]
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Fricas [F] time = 0., size = 0, normalized size = 0. \[{\rm integral}\left ({\left (e^{2} x^{2 \, n} + 2 \, d e x^{n} + d^{2}\right )}{\left (c x^{2 \, n} + b x^{n} + a\right )}^{p}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((e*x^n + d)^2*(c*x^(2*n) + b*x^n + a)^p,x, algorithm="fricas")
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((d+e*x**n)**2*(a+b*x**n+c*x**(2*n))**p,x)
[Out]
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GIAC/XCAS [F(-2)] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: TypeError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((e*x^n + d)^2*(c*x^(2*n) + b*x^n + a)^p,x, algorithm="giac")
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